Summary



























PSE10 QQ.31.02
Consider the circuit shown below, letting V = 0 at the negative terminal of the battery. Switch S1 is closed at time t = 0. At that instant, the electric potential at point c is _____.
simple LR circuit before and after switch closed
A. zero
B. ½ℰ
C. ℰ
D. (Lℰ) ⁄R
Answer















pse9 33.3
What do the voltmeter and ammeter read in the figure?
pse6 33.p.3 circuit
A. 100 V, 4.17 A
B. 100 V, 240 mA
C. 70.7 V, 2.95 A
D. 70.7 V, 1.70 A
Answer



















pse9 33.21
What is the maximum current when a ε0 = 48 V generator at 90 Hz is connected across a 3.70 µF capacitor?
A. 100 mA
B. 75.0 mA
C. 48.0 mA
D. 16.0 mA
Answer















pse9 33.11
What is iL at t = 15.5 ms in the figure if ΔVmax = 80.0 V, ω = 65.0π rad/s, and L = 70.0 mH?
Serway PSE9 figure P33.10 inductor
A. 14.5 mA
B. 132 mA
C. 825 mA
D. 5.60 A
Answer





























 
simple LR circuit before and after switch closed
C. ℰ

No current flows at first because the back emf of the inductor matches the emf of the battery, leaving no potential difference across the resistor to drive current through it. As the back emf dwindles, however, current begins to flow and eventually reach its maximum value when the back emf is zero and the inductor acts like a wire.


















 



C. 70.7 V, 2.95 A




















 



A. 100 mA
solution equation


















 



D. 5.60 A
solution equation