Summary

























POP5 19.15
A uniformly charged ring of radius 10.0 cm has a total charge of 75.0 µC. Find the electric field on the axis of the ring at 100 cm from the center of the ring.
A. 2.41×107 N/C
B. 8.99×106 N/C
C. 1.51×105 N/C
D. 6.64×105 N/C
Answer















klm
What is the sign of the charge on the upper plate in this figure? Knight figure 27.26
A. positive
B. negative
C. could be either
Answer















klm
What is the sign of the charge on the moving particle in this figure? Knight figure 27.26
A. positive
B. negative
C. could be either
Answer















POP4 19.29
An electron moves at 4.50×105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60 N/C. Ignoring gravity, what is its vertical deflection during the time interval in which it travels 3.00 cm horizontally? Knight figure 27.26
A. 4.17 nm
B. 8.89µm
C. 3.75 mm
D. 19.6 cm
Answer















PSE6 q23.18
An electron and a proton are placed in the same electric field. Compare the forces and accelerations:
A. Fe = Fp ... ae = ap
B. Fe = Fp ... ae > ap
C. Fe < Fp ... ae = ap
D. Fe = Fp ... ae < ap
Answer























 



D. 6.64×105 N/C

solution equation





















 



A. positive

The electric field points away from positive charges and toward negative charges.




















 



B. negative

A negatively charged particle will experience a force opposite the direction of the electric field; it gets pulled opposite the field.




















 



C. 3.75 mm























 
B. Fe = Fp ... ae > ap


The magnitude of the forces are the same because the charges are the same, although the electron will be pushed opposite E and the proton will be pushed in the direction of E. The electron mass is smaller so that the same force produces a much larger acceleration.