Summary







































PSE10e Ex.6.6
A small sphere moves in a vertical circle at constant speed. What is the difference in the tensions of the string at the top and the bottom of circle?
ball moving in vertical circle A. mv²/R
B. 2mv²/R
C. mg
D. 2mg
Answer



















klm
What speed will a frictionless roller coaster have at 3.00 m altitude if it began its run from rest at an altitude of 10.0 m?
A. 8.37 m/s
B. 11.7 m/s
C. 70.0 m/s
D. 140 m/s
Answer



















sb5 8.16
A 0.12-kg mass is attached to an unstressed, vertical, k = 40.0 N/m spring and then released. How far does it drop before coming to rest?
A. 7.22 cm
B. 15.4 cm
C. 3.29 cm
D. 5.88 cm
Answer



















PoP5 7.11
A light rigid rod is 77.0 cm long. The rod hangs straight down at rest with a small ball of mass m attached to its bottom end. What minimum horizontal velocity should be given to the ball so that it can swing around in a full circle?
A. 5.49 m/s
B. 30.2 m/s
C. 3.88 m/s
D. 0.770 m/s
Answer























PSE6 8.18
[challenge question] A 2-kg ball is attached to a length of 44.5-N max tension fishing line. If the ball is released when the line is horizontal (θ = 90°), at what angle θ from the vertical will the line break?
pendulum swing before string break A. 74.3°
B. 53.8°
C. 40.8°
D. 19.4°
Answer























PoP5 7.7mod
Two masses are connected as in the figure, and the 5 kg mass is released from rest. What is the speed of m2 just as m1 hits the ground?
A. 4.70 m/s
B. 5.12 m/s
C. 4.43 m/s
D. 6.24 m/s

Answer







































answer
ball moving in vertical circle
D. 2mg

The tension at the top is reduced by the weight, Ttop = mv²/R − mg. The tension at the bottom is increased by the weight, Tbottom = mv²/R + mg. Hence Tbottom − Ttop = 2mg



















answer

B. 11.7 m/s
solution equation
























answer

D. 5.88 cm
solution equation
























answer

A. 5.49 m/s
solution equation




























 


pendulum swing before string break
C. 40.8°
solution equation
































 

A. 4.70 m/s
solution equation