Lecture learning outcomes
A student who masters the topics in this lecture will be able to:
describe how de Broglie waves explained why electrons in allowed orbits do not radiate
describe the basic features of the quantum mechanical model of the atom
explain how an X-ray tube works
calculate the wavelength of Kα X-rays for an element of atomic number Z
describe the operating principles of a laser, and calculate the energy delivered by laser beam during a time interval Δt when given the beam intensity I and cross-sectional area A
A beam of light with a frequency greater than the cutoff frequency shines on the emitter. If the frequency of the light is increased (the color is made bluer) while the intensity (energy per time) is held constant, the number of electrons ejected per second from the emitter will _____.
A. increase
B. decrease
C. stay the same Answer
klm
According to the Bohr model of the hydrogen atom, when the electron jumps from the n = 2 orbit
to the n = 3 orbit its kinetic energy _____.
A. increases
B. decreases
C. stays the same Answer
Walker5e 31.29
An electron in the n = 5 level of hydrogen remains for 51 ns before jumping down to a lower
level. How many orbits did it complete while it was in the n = 5 level?
A. 1.90×10−14 orbits
B. 5 orbits
C. 51 orbits
D. 2.68×106 orbits Answer
klm
How many different states are possible for an electron whose principal quantum number is
n = 4?
A. 8
B. 18
C. 32
D. 50 Answer
sj6 42.38
What is the probable electronic configuration of a neutral atom of element 110?
A. [Rn] 5f 14 6d 2 6f 6
B. [Rn] 5f 14 6d 0 6f 8
C. [Rn] 5f 14 6d 8 7s2
D. [Rn] 5f 16 6d 6 7s2 Answer
Walker5 31.61
Using the Bohr model, estimate the energy of a Kα X-ray emitted by lead (Z = 82).
A. 14 keV
B. 67 keV
C. 82 keV
D. 207 keV Answer
Walker5e 31.84
Suppose a laser emits 1.49×1019 photons per second, half with a wavelength of 488.0 nm and half with a wavelength of 514.5 nm. What is the power output of this laser in watts?
A. 1.49 W
B. 5.76 W
C. 5.91 W
D. 6.07 W Answer
Walker5e 31.64a
Consider an X-ray tube that uses platinum (Z = 78) as its target. Use the Bohr model to estimate the minimum kinetic energy electrons must have in order for Kα X-rays to just appear in the X-ray spectrum of the tube.
A. 80.6 keV
B. 60.5 keV
C. 20.5 keV
D. 13.6 eV Answer
Walker5e 31.87
How would the number of photons emitted per second by a yellow laser compare to the number emitted per second by a red laser that has the same power output?
A. The yellow Kr laser emits more photons per second.
B. The yellow Kr laser emits fewer photons per second.
C. The yellow Kr laser emits the same number of photons per second. Answer
B. decrease
Increasing the frequency of the light means that each photon carries more energy. In order for the intensity to remain constant, there must be fewer photons per second in the beam of light. Because fewer photons hit the surface per second, fewer electrons are ejected per second (but the average kinetic energy of these photoelectrons will be greater because each photon delivers more energy).
B. decreases
According to the Bohr model the speed of the orbiting electron is inversely
proportional to the quantum number n, so if the electron jumps to an orbit with a higher n it will
slow down and its kinetic energy will decrease.
D. 2.68×106 orbits
C. 32
C. [Rn] 5f 14 6d 8 7s2 Use the diagrams above to determine that the 7s subshell will fill up before the 5f or 6d subshells. Along the block of elements from 103 to 112 the 6d subshell is being filled. There is in reality an anomaly here and the actual observed configuration is 5f 14 6d 9 7s1.
B. 67 keV
C. 5.91 W
Each photon contributes to the total power delivered by the laser beam.
A. 80.6 keV
Follow the calculation in Quick Example 31-12.
B. The yellow Kr laser emits fewer photons per second.
The yellow photons each have more energy than the red photons, hence fewer yellow photons are required to produce the same power output as the red laser. We conclude that the yellow laser emits fewer photons per second.